The $I_{1}, I_{2}, I_{3}, I_{4}$ values of an element ‘M’ are 120, 600, 1000 , and 8000 kJ/mole respectively then the formula of its sulphate.

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$M S O_{4}$

$M_{2} {(S O_{4})}_{3}$

$M_{2} S O_{4}$

$M_{3} {(S O_{4})}_{2}$

answer is B.

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Detailed Solution

Due to attainment of stable configuration after losing 3 electrons, there is sudden increase in I4 from I3, hence it has 3 electrons in the valence shell. $M^{+ 3} {({SO}_{4})}^{- 2} \to M_{2} {({SO}_{4})}_{3}$

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