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Q.

The image for the converging beam after refraction through the curved surface (in the given figure) is formed at a distance ‘x’. Then the value of  ‘x’ is 
[radius of refracting surface  AB is 20cm, refractive index of the medium on left side of the AB is n=32 and that on right side is n=1]

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a

x=1807cm

b

x=40 cm

c

x=403 cm

d

x=−403 cm

answer is A.

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Detailed Solution

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From diagram and using the formula μ2v−μ1u=μ2−μ1R

1V−32×30=1−32+20

1V=−140+120=+140V=40 cm.

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