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The image of an illuminated square is obtained on a screen with the help of a converging lens. The distance of the square from the lens is 40 cm. The area of the image is 9 times that of the square. The focal length of the lens is __________

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36 cm

27 cm

30 cm

60 cm

answer is A.

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Detailed Solution

$v = 9 u = 360 cm$
$\begin{array}{l} \frac{1}{v} - \frac{1}{u} = \frac{1}{f} \Rightarrow \frac{1}{360} + \frac{1}{40} = \frac{1}{f} \\ \frac{1}{f} = \frac{1 + 9}{360} = \frac{10}{360} = 36 \\ f = 36 cm \end{array}$

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