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The image of an object placed on the principal axis of a concave mirror of focal length 12cm is formed at a point which is 10cm more distance from the mirror than the object. The magnification of the image is

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8/3

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2.5

answer is D.

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Detailed Solution

If
$\begin{array}{l} u = x \\ ϑ = 10 + x \\ f = 12 c m \\ \frac{1}{u} + \frac{1}{v} = \frac{1}{f} \\ \frac{1}{x} + \frac{1}{10 + x} = \frac{1}{12} \to s o l v i n g \\ u = x = 20 c m \\ ϑ = 30 c m \\ |M| = |v / u| = 1.5 \end{array}$

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