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The image of point P when viewed from top of the slabs will be

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2 cm above P

1.5 cm above P

2 cm below P

1 cm above P

answer is D.

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Detailed Solution

$x = \frac{d_{1}}{μ_{1}} + \frac{d_{2}}{μ_{2}} + \frac{d_{3}}{μ_{3}} = \frac{1.5}{1.5} + \frac{1.5}{1.5} + \frac{2}{1} = 4 cm$
Shift $= 5 - 4 = 1 cm$

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