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The impossible set of quantum numbers is

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$n = 2, l = 0, m = + 1, s = \frac{1}{2}$

$n = 2, l = 0, m = 0, s = + \frac{1}{2}$

$n = 2, l = 1, m = 0, s = \frac{1}{2}$

$n = 3, l = 1, m = - 1, s = \frac{1}{2}$

answer is D.

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If l=0 ‘m’ must be ‘0’ but not +1

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