The incorrect expression among the following is

$\mathrm{\Delta G}={\mathrm{\Delta G}}^{\circ }+\mathrm{RT}\text{ In }\mathrm{Q}$
at equillibrium $\mathrm{Q}+{\mathrm{K}}_{\mathrm{eq}}\mathrm{\&}\mathrm{\Delta G}=0$
${\mathrm{\Delta G}}^{\circ }=-\mathrm{RT}\text{ In }{\mathrm{K}}_{\mathrm{eq}}$
${\mathrm{K}}_{\mathrm{eq}}={\mathrm{\Delta G}}^{\circ }/\mathrm{RT}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}\hspace{0.25em}{\mathrm{\Delta G}}^{\circ }={\mathrm{H}}^{\circ }-{\mathrm{T\Delta S}}^{\circ }$
From above equations
$\begin{array}{l}{\mathrm{\Delta H}}^{\circ }-{\mathrm{T\Delta S}}^{\circ }=-\mathrm{RT}\text{ In }{\mathrm{K}}_{\mathrm{eq}}\text{ (or) }\\ \text{ In }{\mathrm{K}}_{\mathrm{eq}}=\left(\frac{\mathrm{\Delta H}-{\mathrm{T\Delta S}}^{\circ }}{\mathrm{RT}}\right)=\left(\frac{{\mathrm{T\Delta S}}^{\circ }-{\mathrm{OH}}^{\circ }}{\mathrm{RT}}\right)\end{array}$