Q.

The incorrect order of second ionization energies in the following is

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a

S > P

b

Cr > Mn

c

Na > Mg

d

Rb > K

answer is A.

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Detailed Solution

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We know that as we go down the group, the values of ionization energy(IE) decrease and as we move across the period from left to right , the value of ionization energy increases gradually.

And, from the above option Rb and K belongs to same group and atomic number of K is 19 and Rb is 37 ,then Ionisation energy of K>Rb.

same trends are possible in case of IE2.

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