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The incorrect statement for 14 g of CO is

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It corresponds to same mole of CO and N₂

It occupies 2.24 litre at NTP

It corresponds to $\frac{1}{2}$ mole of CO

It corresponds to 3.01 x 10²³molecules of CO

answer is A.

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Detailed Solution

14 g of CO = $\frac{14}{28}$ = 0.5 mole
0.5 mole = 3.01 x 10²³ molecules
The molecular weight of
CO = (12 +16) = 28
The molecular weight of
N₂=14+14=28
Therefore, the incorrect statement is, that it occupies 2.24 litre at NTP.

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