The increase in entropy of 1 kg of ice at 200 K which is heated to 400 K (super heated steam) at constant atmospheric pressure, will be :

Given That :

$C_p\left(\text{ ice }\right)=2.09\times {10}^3\mathrm{J}/\mathrm{kg}\text{ degree, }$

$C_p\left(\text{ water }\right)=4.18\times {10}^3\mathrm{J}/\mathrm{kg}\text{ degree, }$

$C_p\left(\text{ steam }\right)=2.09\times {10}^3\mathrm{J}/\mathrm{kg}\text{ degree }$

$L\left(\text{ ice, }273\mathrm{K}\right)=3.34\times {10}^5\mathrm{J}/\mathrm{kg}$

$L\left(\text{ water, }373\mathrm{K}\right)=22.6\times {10}^5\mathrm{J}/\mathrm{kg}$

Express your answer (in ${\mathrm{JK}}^{-1}$ ) by rounding off to the nearest integer