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The inductance of a closed-packed coil of 400 turns is 8 mH. A current of 5 mA is passed through it. The magnetic flux through each turn of the coil is

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$\frac{1}{4 π} μ_{0} Wb$

$\frac{1}{2 π} μ_{0} Wb$

$\frac{1}{3 π} μ_{0} Wb$

$0 .4 μ_{0} Wb$

answer is A.

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Detailed Solution

$Nϕ = Li \Rightarrow ϕ = \frac{Li}{N} = \frac{8 \times 10^{- 3} \times 5 \times 10^{- 3}}{400} = 10^{- 7} = \frac{μ_{0}}{4 π} W b$

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