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Q.

The inert compound toward water would be :

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a

${SiCl}_{4}$

b

${CCl}_{4}$

c

${PCl}_{3}$

d

${BCl}_{3}$

answer is B.

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Detailed Solution

${SiCl}_{4}$ $s i \to 1 s^{2} 2 s^{2} 2 b^{6} 3 s^{2} 3 b^{2}$

availability of vacant free d- orbitals.

${CCl}_{4} \to 15^{2} 2 S^{2} 2 p^{2}$

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