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Q.

The initial temperature of a gas is $200 K$ . The gas is contained in closed rigid vessel. If the pressure of the gas is increased by 5%. calculate the increase in temperature of the gas:

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a

$1^{0} C$

b

$2 K$

c

$4^{0} C$

d

$10^{0} C$

answer is D.

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Detailed Solution

Volume of gas is constant

$\frac{T_{1}}{T_{2}} = \frac{P_{1}}{P_{2}}$

$\frac{200}{(200 + ∆ T)} = \frac{P}{1.05 P}$

210P = 200P + P. $∆ T$

$\frac{10 P}{P} = ∆ T = 10^{0} C$

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