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Q.

The initial temperature of a liquid is (80.0±0.1)0C. After it has been cooled, its temperature is (10.0±0.1)0C. The fall in temperature in degree centigrade is

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a

70.0±0.1

b

70.0±0.3

c

70.0±0.2

d

70.0

answer is C.

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Detailed Solution

When quantities are subtracted, their maximum absolute errors are added up.

∴            Result=(80−10)±(0.1+0.1)=70±0.2

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