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The initial velocity of a particle is given by u² = v² - 2gx where x is the distance covered. If u = 18 kmh^-1 , g = 1000 cm / s² x = 150 cm then v = ____ m/s

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$\sqrt{45}$

$\sqrt{55}$

$\sqrt{35}$

$\sqrt{65}$

answer is B.

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Detailed Solution

$v^{2} = u^{2} + 2 gx$

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