The initial velocity of the particle is 10 m / sec and its retardation is 2m / sec². The distance moved by the particle in the 5th second of its motion is ________.
Choose the correct option from the following.

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75 m

50 m

19 m

1 m

answer is A.

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Detailed Solution

Given that initial velocity, u = 10 m/sec.

Acceleration a = 2 m/sec²

The distance moved by the particle in the 5th second of its motion can be calculated as:

$S_{n} = u - \frac{a}{2} (2 n - 1) S_{n} = 10 - \frac{2}{2} (2 \times 5 - 1)$

$= 1 m$

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