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Q.

The initial velocity of the particle is 10 m / sec and its retardation is 2m / sec2. The distance moved by the particle in the 5th second of its motion is ________.

Choose the correct option from the following.

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a

75 m

b

50 m

c

19 m

d

1 m

answer is A.

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Detailed Solution

Given that initial velocity, u = 10 m/sec.

Acceleration a = 2 m/sec2

The distance moved by the particle in the 5th second of its motion can be calculated as:

Sn=u-a2(2n-1) Sn=10-22(2×5-1)

      =1 m

 

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