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The inner diameter of the cylindrical wooden pipe is 24cm and its outer diameter is 28cm. The length of the pipe is 35cm. Find the mass of the pipe if 1cm3 of wood has a mass of 0.6g.

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8.652kg

3.152kg

9.852kg

3.432kg

answer is D.

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Detailed Solution

We have the inner diameter = 24 cm
Outer diameter = 28 cm
Outer radius

⇒ Length of pipe (h) = 35 cm
Outer volume = πR2 h

Inner volume = πr2 h

Volume of wood = Outer volume – Inner volume
= 21560 – 15840
= 5720 cm3
∴ Mass of pipe = 5720 × 0.6 g
= 3432 g = 3.432 kg

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