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Q.

The inner part of an optical fiber has a refractive index of 1.68 and the outer part has a refractive index of 1.44. The fiber's numerical aperture is:


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a

0.5653

b

0.6653

c

0.7653

d

0.8653 

answer is D.

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Detailed Solution

Concept: When light travels from an optically denser to an optically rarer medium, if the angle of incidence is greater than a critical angle, it is reflected back into the optically denser medium from the interface between the two media.So, the formula for numerical aperture of an optical fiber is μ 1 2 − μ 2 2  
 μ1= 1.68
μ2=1.44
∴   Numerical aperture
= 1.68 2 − 1.44 2 = 2.8224−2.0736 = 0.7488 =0.8653  
Hence, the correct option is 4.
 
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