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Q.

The input resistance of a common emitter transistor amplifier, if the output resistance is 500 kΩ, the current gain α = 0.98 and power gain is 6.0625 x 106, is

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a

100 Ω

b

300 Ω

c

198 Ω

d

400 Ω

answer is C.

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Detailed Solution

Voltage  gain, Av=βR2R1Also,  current  gain, β=α1−α=0.981−0.98=49Av=49500×103R1Power  gain=6.0625×106=49×500×103R1×49∴R1=198 Ω

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