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The instantaneous value of current and emf in an AC circuit are $I = \frac{1}{\sqrt{2}} \sin (314 t) A and E = \sqrt{2} \sin (314 t - \frac{π}{6}) V$ , respectively. The
phase difference between E and I (with respect to I) will be

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$- \frac{π}{3} rad$

$- \frac{π}{6} rad$

$\frac{π}{6} rad$

$\frac{π}{3} rad$

answer is A.

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Detailed Solution

$I = \frac{1}{\sqrt{2}} \sin (314 t) A; E = \sqrt{2} \sin (314 t - \frac{π}{6}) V$
with respect to current, the emf is lagging. So phase difference is $ϕ = - \frac{π}{6}$

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