The instantaneous values of current and voltage in an A.C. circuit are I=4sin(ωt) and E=100cos(ωt+π3) respectively.The phase difference between voltage and current is

I=I0sinωt+ϕ; E=E0sinωt+ϕI=4sinωt; E=100sinωt+π2+π3 Phase diff. between I and E=π3+π2=5π6

The instantaneous values of current and voltage in an A.C. circuit are I=4sin(ωt) and E=100cos(ωt+π3) respectively.The phase difference between voltage and current is

I=I0sinωt+ϕ; E=E0sinωt+ϕI=4sinωt; E=100sinωt+π2+π3 Phase diff. between I and E=π3+π2=5π6

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The instantaneous values of current and voltage in an A.C. circuit are $I = 4 \sin (ω t) a n d E = 100 \cos (ω t + \frac{π}{3})$ respectively.
The phase difference between voltage and current is

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$\frac{π}{3}$

$\frac{2 π}{3}$

$\frac{5 π}{6}$

$\frac{7 π}{6}$

answer is C.

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Detailed Solution

$\begin{array}{l} I = I_{0} \sin (ω t + ϕ); \\ E = E_{0} \sin (ω t + ϕ) \\ I = 4 \sin ω t; \\ E = 100 \sin (ω t + \frac{π}{2} + \frac{π}{3}) \\ Phase diff. between I and E = \frac{π}{3} + \frac{π}{2} = \frac{5 π}{6} \end{array}$

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