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Q.

The integer ‘k’, for which the inequality  x22(3k1)x+8k27>0 is valid for every x in R, is

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a

2

b

0

c

3

d

4

answer is D.

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Detailed Solution

x22(3k1)x+8x27>0 The roots are imaginary or (real and equal)
  Discriminant 04(3k1)24×1×(8k27)09k26k+18k2+70
k25k+80(k4)(k2)0k[2,4] .
The number of integer values of k is 3.

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