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Q.

The integer k for which the inequality x22(4k1)x+15k22k7>0 is valid for any x, is

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a

2

b

0

c

3

d

4

answer is B.

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Detailed Solution

detailed_solution_thumbnail

The given inequality is valid for any ‘x’, if and only if Δ<0 as a=1>0

Discriminant is negative. 

i.e if  4(4K1)24(15K22K7)<0

i.e if K26K+8<0

(K4)(K2)<0 2<K<4 K=3

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