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Q.

The integer ‘k’ for which the inequality x22(3k1)x+8k27>0 is valid for every x in R, is

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a

4

b

2

c

0

d

3

answer is D.

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Detailed Solution

x22(3k1)x+8k27>0The roots are imaginary or(real and equal)

Discriminant 04(3k1)24×1×8k2709k26k+18k2+70

k26k+80(k4)(k2)0k[2,4]

The number of integer values of k is 3.

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