The integral roots of $x^4-x^3-19x^2+49x-30=0$ is

Given equation is

$\begin{array}{l}{x}^4-x^3-19x^2+49x-30=0\\ \Rightarrow x^3(x-1)-19x(x-1)+30(x-1)=0\\ \Rightarrow (x-1)\left(x^3-19x+30\right)=0\\ \Rightarrow (x-1)=0,\left(x^3-19x+30\right)=0\end{array}$

Also, $\left(x^3-19x+30\right)=0$

$\begin{array}{l}\Rightarrow x^2(x-2)+2x(x-2)-15(x-2)=0\\ \Rightarrow (x-2)\left(x^2+2x-15\right)=0\\ \Rightarrow (x-2)\left(\right(x+5\left)\right(x-3)=0\\ \Rightarrow x=2,3,-5\end{array}$

Hence, the integral roots are 1, 2, 3, and-5.