The intensity of light from a source is $\frac{500}{π} W / m^{2}$ . Find the amplitude of electric field in this wave-

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$\sqrt{3} \times 10^{2} N / C$

$2 \sqrt{3} \times 10^{2} N / C$

$\frac{\sqrt{3}}{2} \times 10^{2} N / C$

$2 \sqrt{2} \times 10^{1} N / C$

answer is B.

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Detailed Solution

$I = \frac{1}{2} \in_{0} c E_{0}^{2} E_{0} = \sqrt{\frac{2 I}{\in_{0} c}} o r \sqrt{\frac{2 \times 500 \times 10^{9} \times 36 π}{π \times 3 \times 10^{8}}} E_{0} = 2 \sqrt{3} \times 10^{2} N / C$

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