The intensity of magnetic induction at the centre of a circular coil is B. What happens to the magnetic field if the number of turns and radius are doubled?

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halved

quadrupled

doubled

remaims same

answer is C.

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Detailed Solution

$\begin{array}{l} B = \frac{μ_{0} ni}{2 r}; i = remaining same . \\ B \propto \frac{n}{r}; \frac{B_{1}}{B_{2}} = \frac{n}{2 n} \times \frac{2 r}{r} = 1 ∴ B_{2} = B \end{array}$

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