The Intensity of sound of loudness level 60dB is n×10−4 watt/m2 . Find n.

β=10 log10II0 ⇒60=10 log10 II0 ⇒I=I0×106 ⇒I=10−12×106 ⇒I=10−6 watt/m2 ⇒I=0.01×10−4 watt/m2

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The Intensity of sound of loudness level 60dB is $n \times 10^{- 4} w a t t / m^{2}$ . Find n.

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Detailed Solution

$β = 10 \log_{10} (\frac{I}{I_{0}}) \Rightarrow 60 = 10 \log_{10} (\frac{I}{I_{0}}) \Rightarrow I = I_{0} \times 10^{6} \Rightarrow I = 10^{- 12} \times 10^{6} \Rightarrow I = 10^{- 6} w a t t / m^{2} \Rightarrow I = 0.01 \times 10^{- 4} w a t t / m^{2}$

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