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Q.

The intensity ratio  of the two interfering beams of light is β What is the value of ImaxImin/Imax+Imin?

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a

2β

b

2β/(1+β)

c

(1+β)/2β

d

2/(1+β)

answer is B.

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Detailed Solution

a1/a22=β  or  a1/a2=β Imax=a1+a22  and  Imin=a1a22 so ImaxIminImax+Imin=4a1a22a12+a22 =4a1/a221+a12/a22=2β(1+β)

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