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Q.

The intensity ratio of two interfering beams of light is $β$ , what is the value of $\frac{I_{max} - I_{min}}{I_{max} + I_{min}} ?$

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a

$2 \sqrt{β}$

b

$\frac{2 \sqrt{β}}{1 + β}$

c

$\frac{2}{1 + β}$

d

$\frac{1 + β}{2 \sqrt{β}}$

answer is B.

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Detailed Solution

detailed_solution_thumbnail

$I_{max} = {(\sqrt{I_{1}} + \sqrt{I_{2}})}^{2}$

$I_{min} = {(\sqrt{I_{1}} - \sqrt{I_{2}})}^{2} and β = \frac{I_{1}}{I_{2}}$

$Substitute in \frac{I_{max} - I_{min}}{I_{max} + I_{min}}$

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