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Q.

The interior angles of a polygon are in A.P. The smallest angle is 120°  and the common difference is 5° . Then the number of sides of the polygon is

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a

answer is I.

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Detailed Solution

n2[2(120)+(n1)5]=(2n4)90°

n[240+5n5]=(2n4)180

240n+5n25n=360n720

5n2365n+240n+720=0

5n2125n+720=0

n225n+144=0

(n16)(n9)=0

n=16  (or) 9.

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The interior angles of a polygon are in A.P. The smallest angle is 120°  and the common difference is 5° . Then the number of sides of the polygon is