The intermediate compound formed in Frankland's reaction is:

Concept- The reaction involving the preparation of dialkyl zinc from zinc and zinc alkyl iodide is called Frankland’s reaction. The reaction sequence is as follows-

R - I + Zn → R - Zn - I

R- Zn - I + Zn → R - Zn. + . Zn - I

R - Zn. + >Zn - I + R - I → R - R + ZnI₂
 

The Wurtz reaction and the Frankland reaction are comparable. Zinc is utilised in the Frankland reaction instead of the Wurtz reaction's sodium. Frankland's reaction is the process by which dialkyl zinc is created from zinc and alkyl iodide. 
 

Diethyl zinc was the first synthetically created organometallic chemical. An unstable radical is created during the reaction. This reaction can be used to create symmetric alkanes. This reaction uses dry ether as a solvent, which aids in the formation of free radicals and protects Zn from moisture. 
 

We can infer this from the way that Haloalkane and Zinc are ingested in a 2:1 ratio. RZnI is generated when they are combined in a 1:1 ratio as opposed to R-R.
Hence, the correct answer is option c.