The internal angle bisector of angle C of a triangle ABC with sides AB, AC and BC are $y = 0,$
$3x+2y=0\text{ and }2x+3y+6=0$ respectively, is $px + qy + 6 = 0$. Then value of $p + q$ is _______

Bisector at $\frac{|3x+2y|}{\sqrt{13}}=\frac{|2x+3y+6|}{\sqrt{13}}$ 

$\Rightarrow x-y-6=0\text{ and }5x+5y+6=0$

According to given equations of sides, internal angle bisector at $C$ will have negative slope.
Image of $A$ wil lie on $BC$ with respect to both bisectors.