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Q.

The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is

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a

6400 J

b

7900 J

c

8900 J

d

5400 J

answer is D.

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Detailed Solution

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Heat given to a system (Q) is equal to the sum of increase in the internal energy (u) and the work done ( W) by the system against the surrounding and I cal  = 4.22 J.

According to first law of thermodynamics.

U = Q - W

 = 2 × 4.2 × 1000-500 = 7900 J 

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