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The internal energy of a gas is given by $U = 2 p V$ . It expands from $V_{0}$ to $2 V_{0}$ against a constant pressure $p_{0}$ . The heat absorbed by the gas in the process is

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$p_{0} V_{0}$

$3 p_{0} V_{0}$

$4 p_{0} V_{0}$

$2 p_{0} V_{0}$

answer is C.

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Detailed Solution

$W = p Δ V = p_{0} (2 V_{0} - V_{0}) = p_{0} V_{0}$

$Δ U = U_{f} - U_{i}$

$= 2 p_{0} (2 V_{0}) - 2 p_{0} V_{0}$

$= 2 p_{0} V_{0}$

$Q = W + Δ U = 3 p_{0} V_{0}$

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