The internal measurement of a cuboidal room $\text{15m }\times \text{ 6m }\times \text{ 4m}$.The room has to be painted along with the ceiling. If cost of painting is Rs $17$ per ${\text{m}}^2$, Find the total cost to be paid.

Concept: The surface area of a cuboid can be defined as the total amount of the area of all its surfaces. Because a cuboid is a three-dimensional solid shape, its surface area is determined by its length, width, and height.

Here, $l=15,b=6,h=4$.

Surface area of cuboid $=2(lb+bh+lh)$

$\Rightarrow 2(15\times 6+6\times 4+15\times 4)$

$\Rightarrow 348{\text{cm}}^2$

Here, the cost of painting is Rs 17 per ${\text{m}}^2$.

Now, total cost $=348\times 17=5916$.

Hence, the total cost to be paid is Rs. 5916.