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The interval of increase of the function $y =$
$x - 2 \sin x$ if $0 \leq x \leq 2 π$ is

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$(0, π)$

$(π / 2, π)$

$(π / 3, 5 π / 3)$

answer is D.

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Detailed Solution

$1 - 2 \cos x > 0$ if $\cos x < 1 / 2 \Rightarrow x \in (\frac{π}{3}, \frac{5 π}{3}) .$

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