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Q.

The inversion of cane sugar proceeds with half life of 50 minutes at pH = 5 for any concentration of sugar. However if pH=6. the half life changed to 500 minutes. The law expression of sugar inversion can be written as:

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a

r=K[ sugar ]1H+0

b

r=K[ sugar ]1H+1

c

r=K[ sugar ]0H+0

d

r=K[ sugar ]2H+0

answer is C.

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Detailed Solution

Here, the half time is,

t1/2(a)1n 50500=1051061n101=101nn=2

t1/2= constant for any [sugar]

 Order w.r.t. sugar= 1

r=k[ sugar ]1H+1

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The inversion of cane sugar proceeds with half life of 50 minutes at pH = 5 for any concentration of sugar. However if pH=6. the half life changed to 500 minutes. The law expression of sugar inversion can be written as: