The inward and outward electric flux for a closed surface in units of N–m²/C are respectively 8 × 10³ and 4 × 10³. Then the total charge inside the surface in S.I. units is (where $\in_{o}$ = permittivity in free space)

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4 × 10³

$\frac{(- 4 \times 10^{3})}{\in_{0}}$

$- 4 \times 10^{3} \in_{0}$

– 4 × 10³

answer is D.

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Detailed Solution

$\begin{array}{l} ϕ_{out} - ϕ_{in} = \frac{q}{ε_{0}} \\ 4 \times 10^{3} \times - 8 \times 10^{3} = \frac{q}{ε_{0}} \Rightarrow q = - 4 \times 10^{3} ε_{0} \end{array}$

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