The inward and outward electric flux from a closed surface are respectively 8 x 10³ and 4 x 10³ units. Then the net charge inside the closed surface is

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$\frac{4 \times 10^{3}}{ε_{0}} coulomb$

$4 \times 10^{3} coulomb$

$\frac{- 4 \times 10^{3}}{ε_{0}} coulomb$

$- 4 \times 10^{3} ε_{0} coulomb$

answer is B.

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Detailed Solution

Here $Φ = 4 \times 10^{3} - 8 \times 10^{3}$
$= - 4 \times 10^{3}$
According to Gauss's law,
$\begin{aligned} Φ = \frac{1}{ε_{0}} \times q or q = ε_{0} Φ \\ ∴ q = - 4 \times 10^{3} ε_{0} . \end{aligned}$

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