The ion of an element have $3$positive charges. Mass number of the atom is$27$as well as the number of neutrons is $14$. What is the numeral of electrons in the ion?

Since, mass number and number of neutrons, we can compute the number of protons or electrons which is $13$ (Mass number - Number of neutrons). Therefore, the electronic configuration of this element would be $2, 8, 3.$ In arrange to become constant it would lose the last $3$ electrons and gain $3$ positive charges as known in the question. So, the resultant ion is left with $10$ electrons.

As per the given data,
$3$ positive charge
$27$ mass number
$14$ neutron

The mass number of any atom = No. of protons + No. of neutrons
$27 =$No. of protons $+ 14$
No. of protons $= 13$
No. of protons in atom = No. of electrons in atom $= 13$
Number of electrons in ion $= 13\mathit{ – }3$
                                            $= 10$
  

Hence, the ion of an element have$3$positive charges.Mass number of the atom is$27$as well as the number of neutrons is $14$ then the number of electron in the ion is $10$.