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Q.

The ion that cannot be precipitated by passing both  HCl and H2S is

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a

Sn+2

b

Ag+

c

Cu+

d

Pb+2

answer is D.

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Detailed Solution

  • Pb2+,Cu+ and Ag+ can be precipitated by HCl as well as H2​S as their insoluble chlorides and sulfides respectively.
  • While Sn2+ reacts with HCl to form soluble stannous chloride but reacts with H2​S to form a brown precipitate of insoluble stannous sulfide.
  •  Sn2++HCl→SnCl2​(soluble)+2H+
    Sn2++H2​S → SnS↓(brown ppt.)+2H+


 

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