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Q.

The ion that cannot be precipitated by passing both HCl and $H_{2} S$ is

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a

${Sn}^{+ 2}$

b

${Ag}^{+}$

c

${Cu}^{+}$

d

${Pb}^{+ 2}$

answer is D.

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Detailed Solution

Pb²⁺,Cu⁺ and Ag⁺ can be precipitated by HCl as well as H₂S as their insoluble chlorides and sulfides respectively.
While Sn²⁺ reacts with HCl to form soluble stannous chloride but reacts with H₂S to form a brown precipitate of insoluble stannous sulfide.
Sn²⁺+HCl→SnCl₂(soluble)+2H⁺
Sn²⁺+H₂S → SnS↓(brown ppt.)+2H+

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