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The ionic conductances of octahealral complexes.
I) $Pt C l_{4} . 5 {NH}_{3}$
II) $Pt C l_{4} . 4 {NH}_{3}$
III) $Pt C l_{4} . 3 {NH}_{3}$
IV) $Pt C l_{4} . 2 {NH}_{3}$

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$IV < III < I < II$

$I < II < III < IV$

$IV < III < II < I$

$III < IV < II < I$

answer is B.

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Detailed Solution

I) $Pt C l_{4} .5 {NH}_{3} \Rightarrow [Pt {({NH}_{3})}_{5} C l] \overset{Ionisation}{⟶} 4 Ions$

II) $Pt C l_{4} \cdot 4 {NH}_{3} \Rightarrow [Pt {({NH}_{3})}_{4} C l_{2}] C l_{2} \overset{Ionisation}{⟶} 3 Ions$

III) $Pt C l_{4} . 3 {NH}_{3} \Rightarrow [Pt {({NH}_{3})}_{3} C l_{2}] C l \overset{}{\to} 2 Ions$

IV) $Pt C l_{4} . 2 {NH}_{3} \Rightarrow [Pt {({NH}_{3})}_{2} C l_{4}] \to_{Ionis a t i o n}^{No} Neutral Complex$

Conductance & No. of Ions

$∴ Molar Ionic Conductance Order : IV < III < II < I$

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