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Q.

The ionic product of water is $10^{- 14}$ . The $H^{+}$ ion concentration in $0.1 MNaOH$ solution is

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a

$10^{- 13} M$

b

$10^{- 4} M$

c

$10^{- 1} M$

d

$10^{- 11} M$

answer is B.

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Detailed Solution

$K_{w} = 10^{- 14}$

$[{OH}^{-}] = 0.1 = 10^{- 1}$

$∴ [H^{+}] = \frac{10^{- 14}}{10^{- 1}} = 10^{- 13}$

Hence the correct answer (B) $10^{- 13} M$

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The ionic product of water is 10-14. The H+ ion concentration in 0.1MNaOH solution is