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Q.

The ionisation energy of hydrogen is 13.6 eV. The energy of the photon released when an electron jumps from the first excited state (n = 2) to the ground state: of hydrogen atom is [WB JEE 2014]

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a

3.4 eV

b

4.53 eV

c

10.2 eV

d

13.6 eV

answer is C.

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Detailed Solution

The energy of the photon  =Rhc112-1n2

⇒  13.611-14=13.64-14

=13.6×34=40.84=10.2eV

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