The ionization constant of a weak electrolyte is $25 \times 10^{- 6}$ and the equivalent conductance of its 0.01 M solution is 19.6 S ${cm}^{2} {eq}^{- 1}$ . The equivalent conductance at infinite dilution of the electrolyte in S ${cm}^{2} {eq}^{- 1}$ is

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384

250

392

196

answer is C.

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Detailed Solution

$\begin{array}{l} \underset{C}{HA} ⇌ \underset{0}{H^{+}} + \underset{0}{A^{-}} \\ C - Cα Cα Cα \end{array}$

Or $K = {Cα}^{2}$

$25 \times 10^{- 6} = 10^{- 2} . α^{2}$

$α = 5 \times 10^{- 2}$

Also $α = \frac{λ_{v}}{λ_{\infty}} = \frac{19 .6}{λ_{\infty}} λ_{\infty} = \frac{19 .6}{5 \times 10^{- 2}} = 392$

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