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Q.

The ionization constant of HCN at 298 K is 4.8 x 10-9 then the ionization constant of its conjugate base is

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a

4.8×10−7

b

2.08×10−6

c

2.08×10−9

d

4.8×10−9

answer is A.

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Detailed Solution

For a conjugate acid – base pair Ka x  Kb = Kw

At 298K, Ka·Kb=10-14

Ka=4.8×10-9;

Kb=10−144.8×10−9=2.08×10−6

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