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The ionization constants of HX, HY, and HZ at 298 K are 10^-4,10^-7 and 10^-9respectively. The correct order of basic strength of the conjugate base is

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$Y^{-} > Z^{-} > X^{-}$

$X^{-} > Y^{-} > Z^{-}$

$Y^{-} > X^{-} > Z^{-}$

$Z^{-} > Y^{-} > X^{-}$

answer is D.

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Detailed Solution

$K_{b} = \frac{K_{w}}{K_{a}}$

$K_{b (X^{-})} = \frac{10^{- 14}}{10^{- 4}} = 10^{- 10}$

$K_{b (Y^{-})} = \frac{10^{- 14}}{10^{- 7}} = 10^{- 7}$

$K_{b (Z^{-})} = \frac{10^{- 14}}{10^{- 9}} = 10^{- 5}$

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