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Q.

The ionization energy of hydrogen atom in terms of Rydberg constant $(R_{H})$ is given by the expression

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a

$R_{H} h c$

b

$R_{H} c$

c

$2 R_{H} h c$

d

$R_{H} N_{A} h c$

answer is A.

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Detailed Solution

$\frac{1}{λ} = R_{H} z^{2} (\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$
For ionization energy, $n_{1} = 1$ and $n_{2} = \infty$

$\frac{1}{λ} = R_{H} I E_{1} = E_{\infty} - E_{1} = \frac{h c}{λ} = R_{H} h c$

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