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Q.

The ionization energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy corresponding to a transition between the 3rd and the 4th orbit is

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a

3.40 eV

b

0.66 eV

c

0.85 eV

d

1.51 eV

answer is D.

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Detailed Solution

n=3 z=1  n=4  z=1

E3=-13.632  E4=-13.642

=-13.69     =-13.616

=-1.51        =-0.85E4-E3=-0.85-(-1.51)

=-0.85+1.51=0.66eV

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The ionization energy of hydrogen atom is 13.6 eV. Following Bohr's theory, the energy corresponding to a transition between the 3rd and the 4th orbit is